3[3x-1]=4[3+3x]

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Solution for 3[3x-1]=4[3+3x] equation:


Simplifying
3[3x + -1] = 4[3 + 3x]

Reorder the terms:
3[-1 + 3x] = 4[3 + 3x]
[-1 * 3 + 3x * 3] = 4[3 + 3x]
[-3 + 9x] = 4[3 + 3x]
-3 + 9x = [3 * 4 + 3x * 4]
-3 + 9x = [12 + 12x]

Solving
-3 + 9x = 12 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.
-3 + 9x + -12x = 12 + 12x + -12x

Combine like terms: 9x + -12x = -3x
-3 + -3x = 12 + 12x + -12x

Combine like terms: 12x + -12x = 0
-3 + -3x = 12 + 0
-3 + -3x = 12

Add '3' to each side of the equation.
-3 + 3 + -3x = 12 + 3

Combine like terms: -3 + 3 = 0
0 + -3x = 12 + 3
-3x = 12 + 3

Combine like terms: 12 + 3 = 15
-3x = 15

Divide each side by '-3'.
x = -5

Simplifying
x = -5

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